what im trying to do is display the contents of an existing file with the addition of a new thing i tryed this and got 0x76fd4ca now the a at the end makes sense because the new edition to the file was "a". the 0x76fd4c part of it was i think the previous part of the file which was (i think) an "h" but in machine code or something.

its like

cout<<file<<charvariable;

anyway i think i got my self in somthing thats a little too advanced for me at this point i think, but it seems so simple.

0x76fd4c is an address in memory, so you are printing a pointer. It's probably because of an array or string.

well heres my code:

CODE

#include <iostream.h> #include <fstream.h> ifstream fin;   //what i use for filein, from fstream.h int main() { fin.open("file.txt"); cout<<fin<<"\n"; fin.close(); system("pause"); }

how do i turn the contents of file.txt into a string? im pretty sure thats what the problem is.

this works:

QUOTE

#include <iostream>//I removed the ".h" because that gives me a compiler error #include <fstream> #include <string>//So we can use the string var type using namespace std;//You also forgot this. I don't know what it does but each time I leave it aside I get an error ifstream fin; int main() { string str;//I use here a string because as far as I know strings aren't limited in size char file[64];//fin.open needs char and as far as I know can windows path have more than 64 chrarachters cout << "Enter a text file to open" << endl; cin >> file; fin.open(file); fin >> str;//I dont know if "str<<fin" is the same best check it out cout << str << endl; fin.close(); system("pause"); }

Check out my topic in the C++ Tips forum. It might help.

QUOTE

#include <iostream>//I removed the ".h" because that gives me a compiler error

There is no ".h" on iostream.

QUOTE

CODE #include <iostream.h>

He had putten one

QUOTE

CODE char file[64];//fin.open needs char and as far as I know can windows path have more than 64 chrarachters

That should be "have not more".