Is there a way to do #define so that the thing that it equals isnt one line?

What do you mean by the "thing it equals"?

like this

#define monkey cout<<"Monkey"<<endl;

is there a way to make the cout<<"Monkey"<<endl; part be more then one line?

You can use the line-extension operator ( \ ) like this:

out of curiosity why do you have to use the "\" operator. That doesn't look like code that requires more than one line. Why dont you just press enter to put it on the new line, because I know C++ ignores white space.

I don't really know what you mean but could it be this:
#define monkey cout<<"Monkey1"<<endl<<"Monkey2"<<endl;

i would use
#define Monkey "1"
#define Monkey "2"
std::cout << Monkey1 << std::end1
std::cout << Monkey2 << std::end1

or something like this

C++ ignores white-space, and so does the C pre-processor -- except for line-feeds. ALL pre-processor directives must take place on a single line, otherwise the pre-processor would have no idea where the #define ends. The only way to get it onto multiple lines is to extend the single line where the #define takes place.

, This is how my compiler does it, or wants me to do it, same with my book, and it works fine

That doesn't make any sense. You never define Monkey1 or Monkey2. Your code would just define Monkey as "2" and then tell you that Monkey1 and 2 are undefined.

Na that may be some strange VC++ code but it's no standard C++!

I use VC++ and I've never seen anything like that. (That worked ;) )